2(B+5)=3(b-2)+23

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Solution for 2(B+5)=3(b-2)+23 equation: 



2(+5)=3(B-2)+23

We move all terms to the left:

2(+5)-(3(B-2)+23)=0

We add all the numbers together, and all the variables

-(3(B-2)+23)+25=0



We calculate terms in parentheses: -(3(B-2)+23), so:

3(B-2)+23

We multiply parentheses

3B-6+23

We add all the numbers together, and all the variables

3B+17

Back to the equation:

-(3B+17)



We get rid of parentheses

-3B-17+25=0

We add all the numbers together, and all the variables

-3B+8=0

We move all terms containing B to the left, all other terms to the right

-3B=-8

B=-8/-3

B=2+2/3

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