2(A+4b+5c)=

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Solution for 2(A+4b+5c)= equation:


Simplifying
2(A + 4b + 5c) = 0
(A * 2 + 4b * 2 + 5c * 2) = 0
(2A + 8b + 10c) = 0

Solving
2A + 8b + 10c = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '-8b' to each side of the equation.
2A + 8b + -8b + 10c = 0 + -8b

Combine like terms: 8b + -8b = 0
2A + 0 + 10c = 0 + -8b
2A + 10c = 0 + -8b
Remove the zero:
2A + 10c = -8b

Add '-10c' to each side of the equation.
2A + 10c + -10c = -8b + -10c

Combine like terms: 10c + -10c = 0
2A + 0 = -8b + -10c
2A = -8b + -10c

Divide each side by '2'.
A = -4b + -5c

Simplifying
A = -4b + -5c

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