2(9d+5)+3(5d-1)=-d+9(d-2)

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Solution for 2(9d+5)+3(5d-1)=-d+9(d-2) equation: 



2(9d+5)+3(5d-1)=-d+9(d-2)

We move all terms to the left:

2(9d+5)+3(5d-1)-(-d+9(d-2))=0

We multiply parentheses

18d+15d-(-d+9(d-2))+10-3=0



We calculate terms in parentheses: -(-d+9(d-2)), so:

-d+9(d-2)

We add all the numbers together, and all the variables

-1d+9(d-2)

We multiply parentheses

-1d+9d-18

We add all the numbers together, and all the variables

8d-18

Back to the equation:

-(8d-18)



We add all the numbers together, and all the variables

33d-(8d-18)+7=0

We get rid of parentheses

33d-8d+18+7=0

We add all the numbers together, and all the variables

25d+25=0

We move all terms containing d to the left, all other terms to the right

25d=-25

d=-25/25

d=-1

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