2(9-2s)+6=2(s-5)-8

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Solution for 2(9-2s)+6=2(s-5)-8 equation:



2(9-2s)+6=2(s-5)-8
We move all terms to the left:
2(9-2s)+6-(2(s-5)-8)=0
We add all the numbers together, and all the variables
2(-2s+9)-(2(s-5)-8)+6=0
We multiply parentheses
-4s-(2(s-5)-8)+18+6=0
We calculate terms in parentheses: -(2(s-5)-8), so:
2(s-5)-8
We multiply parentheses
2s-10-8
We add all the numbers together, and all the variables
2s-18
Back to the equation:
-(2s-18)
We add all the numbers together, and all the variables
-4s-(2s-18)+24=0
We get rid of parentheses
-4s-2s+18+24=0
We add all the numbers together, and all the variables
-6s+42=0
We move all terms containing s to the left, all other terms to the right
-6s=-42
s=-42/-6
s=+7

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