2(9+6z)=-5(2-2z)

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Solution for 2(9+6z)=-5(2-2z) equation: 



2(9+6z)=-5(2-2z)

We move all terms to the left:

2(9+6z)-(-5(2-2z))=0

We add all the numbers together, and all the variables

2(6z+9)-(-5(-2z+2))=0

We multiply parentheses

12z-(-5(-2z+2))+18=0



We calculate terms in parentheses: -(-5(-2z+2)), so:

-5(-2z+2)

We multiply parentheses

10z-10

Back to the equation:

-(10z-10)



We get rid of parentheses

12z-10z+10+18=0

We add all the numbers together, and all the variables

2z+28=0

We move all terms containing z to the left, all other terms to the right

2z=-28

z=-28/2

z=-14

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