2(9+3c)=3(-6c-10)

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Solution for 2(9+3c)=3(-6c-10) equation: 



2(9+3c)=3(-6c-10)

We move all terms to the left:

2(9+3c)-(3(-6c-10))=0

We add all the numbers together, and all the variables

2(3c+9)-(3(-6c-10))=0

We multiply parentheses

6c-(3(-6c-10))+18=0



We calculate terms in parentheses: -(3(-6c-10)), so:

3(-6c-10)

We multiply parentheses

-18c-30

Back to the equation:

-(-18c-30)



We get rid of parentheses

6c+18c+30+18=0

We add all the numbers together, and all the variables

24c+48=0

We move all terms containing c to the left, all other terms to the right

24c=-48

c=-48/24

c=-2

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