2(8z+5)=4(3z+1)

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Solution for 2(8z+5)=4(3z+1) equation: 



2(8z+5)=4(3z+1)

We move all terms to the left:

2(8z+5)-(4(3z+1))=0

We multiply parentheses

16z-(4(3z+1))+10=0



We calculate terms in parentheses: -(4(3z+1)), so:

4(3z+1)

We multiply parentheses

12z+4

Back to the equation:

-(12z+4)



We get rid of parentheses

16z-12z-4+10=0

We add all the numbers together, and all the variables

4z+6=0

We move all terms containing z to the left, all other terms to the right

4z=-6

z=-6/4

z=-1+1/2

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