2(8x-4)-(2x-2)=15-2(3x+4)-3

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Solution for 2(8x-4)-(2x-2)=15-2(3x+4)-3 equation: 



2(8x-4)-(2x-2)=15-2(3x+4)-3

We move all terms to the left:

2(8x-4)-(2x-2)-(15-2(3x+4)-3)=0

We multiply parentheses

16x-(2x-2)-(15-2(3x+4)-3)-8=0

We get rid of parentheses

16x-2x-(15-2(3x+4)-3)+2-8=0



We calculate terms in parentheses: -(15-2(3x+4)-3), so:

15-2(3x+4)-3

determiningTheFunctionDomain
-2(3x+4)+15-3

We add all the numbers together, and all the variables

-2(3x+4)+12

We multiply parentheses

-6x-8+12

We add all the numbers together, and all the variables

-6x+4

Back to the equation:

-(-6x+4)



We add all the numbers together, and all the variables

14x-(-6x+4)-6=0

We get rid of parentheses

14x+6x-4-6=0

We add all the numbers together, and all the variables

20x-10=0

We move all terms containing x to the left, all other terms to the right

20x=10

x=10/20

x=1/2

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