2(8x-4)+(2x)2=70

Solution for 2(8x-4)+(2x)2=70 equation:

2(8x-4)+(2x)2=70

We move all terms to the left:

2(8x-4)+(2x)2-(70)=0

We add all the numbers together, and all the variables

2x^2+2(8x-4)-70=0

We multiply parentheses

2x^2+16x-8-70=0

We add all the numbers together, and all the variables

2x^2+16x-78=0

a = 2; b = 16; c = -78;
Δ = b2-4ac
Δ = 162-4·2·(-78)
Δ = 880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{880}=\sqrt{16*55}=\sqrt{16}*\sqrt{55}=4\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{55}}{2*2}=\frac{-16-4\sqrt{55}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{55}}{2*2}=\frac{-16+4\sqrt{55}}{4}
$