2(8x+2)=4(x+1)

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Solution for 2(8x+2)=4(x+1) equation: 



2(8x+2)=4(x+1)

We move all terms to the left:

2(8x+2)-(4(x+1))=0

We multiply parentheses

16x-(4(x+1))+4=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

16x-4x-4+4=0

We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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