2(8d-8)+d=10(2d+2)

Solution for 2(8d-8)+d=10(2d+2) equation:

2(8d-8)+d=10(2d+2)

We move all terms to the left:

2(8d-8)+d-(10(2d+2))=0

We add all the numbers together, and all the variables

d+2(8d-8)-(10(2d+2))=0

We multiply parentheses

d+16d-(10(2d+2))-16=0


We calculate terms in parentheses: -(10(2d+2)), so:

10(2d+2)

We multiply parentheses

20d+20

Back to the equation:

-(20d+20)


We add all the numbers together, and all the variables

17d-(20d+20)-16=0

We get rid of parentheses

17d-20d-20-16=0

We add all the numbers together, and all the variables

-3d-36=0

We move all terms containing d to the left, all other terms to the right

-3d=36

d=36/-3

d=-12