2(7x-3)-9=8x-(2x-5)+10

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Solution for 2(7x-3)-9=8x-(2x-5)+10 equation: 



2(7x-3)-9=8x-(2x-5)+10

We move all terms to the left:

2(7x-3)-9-(8x-(2x-5)+10)=0

We multiply parentheses

14x-(8x-(2x-5)+10)-6-9=0



We calculate terms in parentheses: -(8x-(2x-5)+10), so:

8x-(2x-5)+10

We get rid of parentheses

8x-2x+5+10

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We add all the numbers together, and all the variables

14x-(6x+15)-15=0

We get rid of parentheses

14x-6x-15-15=0

We add all the numbers together, and all the variables

8x-30=0

We move all terms containing x to the left, all other terms to the right

8x=30

x=30/8

x=3+3/4

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