2(7b+5)=7(b-5)

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Solution for 2(7b+5)=7(b-5) equation: 



2(7b+5)=7(b-5)

We move all terms to the left:

2(7b+5)-(7(b-5))=0

We multiply parentheses

14b-(7(b-5))+10=0



We calculate terms in parentheses: -(7(b-5)), so:

7(b-5)

We multiply parentheses

7b-35

Back to the equation:

-(7b-35)



We get rid of parentheses

14b-7b+35+10=0

We add all the numbers together, and all the variables

7b+45=0

We move all terms containing b to the left, all other terms to the right

7b=-45

b=-45/7

b=-6+3/7

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