2(7-h)=3(h-2)

Solution for 2(7-h)=3(h-2) equation:

2(7-h)=3(h-2)

We move all terms to the left:

2(7-h)-(3(h-2))=0

We add all the numbers together, and all the variables

2(-1h+7)-(3(h-2))=0

We multiply parentheses

-2h-(3(h-2))+14=0


We calculate terms in parentheses: -(3(h-2)), so:

3(h-2)

We multiply parentheses

3h-6

Back to the equation:

-(3h-6)


We get rid of parentheses

-2h-3h+6+14=0

We add all the numbers together, and all the variables

-5h+20=0

We move all terms containing h to the left, all other terms to the right

-5h=-20

h=-20/-5

h=+4