2(7-5y-4)=y-4(5y-6-3y)

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Solution for 2(7-5y-4)=y-4(5y-6-3y) equation: 



2(7-5y-4)=y-4(5y-6-3y)

We move all terms to the left:

2(7-5y-4)-(y-4(5y-6-3y))=0

We add all the numbers together, and all the variables

2(-5y+3)-(y-4(2y-6))=0

We multiply parentheses

-10y-(y-4(2y-6))+6=0



We calculate terms in parentheses: -(y-4(2y-6)), so:

y-4(2y-6)

We multiply parentheses

y-8y+24

We add all the numbers together, and all the variables

-7y+24

Back to the equation:

-(-7y+24)



We get rid of parentheses

-10y+7y-24+6=0

We add all the numbers together, and all the variables

-3y-18=0

We move all terms containing y to the left, all other terms to the right

-3y=18

y=18/-3

y=-6

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