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2(7-3x)+8x=x-12
We move all terms to the left:
2(7-3x)+8x-(x-12)=0
We add all the numbers together, and all the variables
2(-3x+7)+8x-(x-12)=0
We add all the numbers together, and all the variables
8x+2(-3x+7)-(x-12)=0
We multiply parentheses
8x-6x-(x-12)+14=0
We get rid of parentheses
8x-6x-x+12+14=0
We add all the numbers together, and all the variables
x+26=0
We move all terms containing x to the left, all other terms to the right
x=-26
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