2(7+x)=5(x-1,2)+35

Solution for 2(7+x)=5(x-1,2)+35 equation:

2(7+x)=5(x-1.2)+35

We move all terms to the left:

2(7+x)-(5(x-1.2)+35)=0

We add all the numbers together, and all the variables

2(x+7)-(5(x-1.2)+35)=0

We multiply parentheses

2x-(5(x-1.2)+35)+14=0


We calculate terms in parentheses: -(5(x-1.2)+35), so:

5(x-1.2)+35

We multiply parentheses

5x-6+35

We add all the numbers together, and all the variables

5x+29

Back to the equation:

-(5x+29)


We get rid of parentheses

2x-5x-29+14=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5