2(6z-3)=32

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Solution for 2(6z-3)=32 equation: 



2(6z-3)=32

We move all terms to the left:

2(6z-3)-(32)=0

We multiply parentheses

12z-6-32=0

We add all the numbers together, and all the variables

12z-38=0

We move all terms containing z to the left, all other terms to the right

12z=38

z=38/12

z=3+1/6

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