2(6z-12)=32

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Solution for 2(6z-12)=32 equation: 



2(6z-12)=32

We move all terms to the left:

2(6z-12)-(32)=0

We multiply parentheses

12z-24-32=0

We add all the numbers together, and all the variables

12z-56=0

We move all terms containing z to the left, all other terms to the right

12z=56

z=56/12

z=4+2/3

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