2(6z+2)=45

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Solution for 2(6z+2)=45 equation: 



2(6z+2)=45

We move all terms to the left:

2(6z+2)-(45)=0

We multiply parentheses

12z+4-45=0

We add all the numbers together, and all the variables

12z-41=0

We move all terms containing z to the left, all other terms to the right

12z=41

z=41/12

z=3+5/12

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