2(6y-4)=(7y+3)

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Solution for 2(6y-4)=(7y+3) equation: 



2(6y-4)=(7y+3)

We move all terms to the left:

2(6y-4)-((7y+3))=0

We multiply parentheses

12y-((7y+3))-8=0



We calculate terms in parentheses: -((7y+3)), so:

(7y+3)

We get rid of parentheses

7y+3

Back to the equation:

-(7y+3)



We get rid of parentheses

12y-7y-3-8=0

We add all the numbers together, and all the variables

5y-11=0

We move all terms containing y to the left, all other terms to the right

5y=11

y=11/5

y=2+1/5

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