2(6y+2)=28

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Solution for 2(6y+2)=28 equation: 



2(6y+2)=28

We move all terms to the left:

2(6y+2)-(28)=0

We multiply parentheses

12y+4-28=0

We add all the numbers together, and all the variables

12y-24=0

We move all terms containing y to the left, all other terms to the right

12y=24

y=24/12

y=2

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