2(6x-8)=40+4x

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Solution for 2(6x-8)=40+4x equation: 



2(6x-8)=40+4x

We move all terms to the left:

2(6x-8)-(40+4x)=0

We add all the numbers together, and all the variables

2(6x-8)-(4x+40)=0

We multiply parentheses

12x-(4x+40)-16=0

We get rid of parentheses

12x-4x-40-16=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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