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2(6x-5)=4(3x+7)
We move all terms to the left:
2(6x-5)-(4(3x+7))=0
We multiply parentheses
12x-(4(3x+7))-10=0
We calculate terms in parentheses: -(4(3x+7)), so:We get rid of parentheses
4(3x+7)
We multiply parentheses
12x+28
Back to the equation:
-(12x+28)
12x-12x-28-10=0
We add all the numbers together, and all the variables
-38!=0
There is no solution for this equation
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