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2(6x-5)=-3(10-4x)
We move all terms to the left:
2(6x-5)-(-3(10-4x))=0
We add all the numbers together, and all the variables
2(6x-5)-(-3(-4x+10))=0
We multiply parentheses
12x-(-3(-4x+10))-10=0
We calculate terms in parentheses: -(-3(-4x+10)), so:We get rid of parentheses
-3(-4x+10)
We multiply parentheses
12x-30
Back to the equation:
-(12x-30)
12x-12x+30-10=0
We add all the numbers together, and all the variables
20!=0
There is no solution for this equation
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