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2(6x-4)+6=5(x+8)
We move all terms to the left:
2(6x-4)+6-(5(x+8))=0
We multiply parentheses
12x-(5(x+8))-8+6=0
We calculate terms in parentheses: -(5(x+8)), so:We add all the numbers together, and all the variables
5(x+8)
We multiply parentheses
5x+40
Back to the equation:
-(5x+40)
12x-(5x+40)-2=0
We get rid of parentheses
12x-5x-40-2=0
We add all the numbers together, and all the variables
7x-42=0
We move all terms containing x to the left, all other terms to the right
7x=42
x=42/7
x=6
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