2(6x+8)+7x=3x-2(12+4x)

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Solution for 2(6x+8)+7x=3x-2(12+4x) equation:



2(6x+8)+7x=3x-2(12+4x)
We move all terms to the left:
2(6x+8)+7x-(3x-2(12+4x))=0
We add all the numbers together, and all the variables
2(6x+8)+7x-(3x-2(4x+12))=0
We add all the numbers together, and all the variables
7x+2(6x+8)-(3x-2(4x+12))=0
We multiply parentheses
7x+12x-(3x-2(4x+12))+16=0
We calculate terms in parentheses: -(3x-2(4x+12)), so:
3x-2(4x+12)
We multiply parentheses
3x-8x-24
We add all the numbers together, and all the variables
-5x-24
Back to the equation:
-(-5x-24)
We add all the numbers together, and all the variables
19x-(-5x-24)+16=0
We get rid of parentheses
19x+5x+24+16=0
We add all the numbers together, and all the variables
24x+40=0
We move all terms containing x to the left, all other terms to the right
24x=-40
x=-40/24
x=-1+2/3

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