2(6x+4)-6+2x=3(4x+3+1)

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Solution for 2(6x+4)-6+2x=3(4x+3+1) equation: 



2(6x+4)-6+2x=3(4x+3+1)

We move all terms to the left:

2(6x+4)-6+2x-(3(4x+3+1))=0

We add all the numbers together, and all the variables

2(6x+4)+2x-(3(4x+4))-6=0

We add all the numbers together, and all the variables

2x+2(6x+4)-(3(4x+4))-6=0

We multiply parentheses

2x+12x-(3(4x+4))+8-6=0



We calculate terms in parentheses: -(3(4x+4)), so:

3(4x+4)

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

14x-(12x+12)+2=0

We get rid of parentheses

14x-12x-12+2=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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