2(6x+4)-06+2x=3(4x+3)+1

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Solution for 2(6x+4)-06+2x=3(4x+3)+1 equation: 



2(6x+4)-06+2x=3(4x+3)+1

We move all terms to the left:

2(6x+4)-06+2x-(3(4x+3)+1)=0

We add all the numbers together, and all the variables

2x+2(6x+4)-(3(4x+3)+1)-6=0

We multiply parentheses

2x+12x-(3(4x+3)+1)+8-6=0



We calculate terms in parentheses: -(3(4x+3)+1), so:

3(4x+3)+1

We multiply parentheses

12x+9+1

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

14x-(12x+10)+2=0

We get rid of parentheses

14x-12x-10+2=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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