2(6x+3)=7(x+3)

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Solution for 2(6x+3)=7(x+3) equation: 



2(6x+3)=7(x+3)

We move all terms to the left:

2(6x+3)-(7(x+3))=0

We multiply parentheses

12x-(7(x+3))+6=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

12x-7x-21+6=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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