2(6t-3)=12(t-2)+18

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Solution for 2(6t-3)=12(t-2)+18 equation:


2(6t-3)=12(t-2)+18

We simplify the equation to the form, which is simple to understand 
2(6t-3)=12(t-2)+18

Reorder the terms in parentheses
+(+12t-6)=12*(t-2)+18

Remove unnecessary parentheses
+12t-6=+12+*(+t-2+)+18

Reorder the terms in parentheses
+12t-6=+(+12t-24)+18

Remove unnecessary parentheses
+12t-6=+12t-24+18

We move all terms containing t to the left and all other terms to the right. 
+12t-12t=-24+18+6

We simplify left and right side of the equation. 
t=0

0=0

This equation is an identity, so all real numbers are solutions.

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