2(6s+1)=4(s-5)-2

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Solution for 2(6s+1)=4(s-5)-2 equation: 



2(6s+1)=4(s-5)-2

We move all terms to the left:

2(6s+1)-(4(s-5)-2)=0

We multiply parentheses

12s-(4(s-5)-2)+2=0



We calculate terms in parentheses: -(4(s-5)-2), so:

4(s-5)-2

We multiply parentheses

4s-20-2

We add all the numbers together, and all the variables

4s-22

Back to the equation:

-(4s-22)



We get rid of parentheses

12s-4s+22+2=0

We add all the numbers together, and all the variables

8s+24=0

We move all terms containing s to the left, all other terms to the right

8s=-24

s=-24/8

s=-3

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