2(6m-12)=3(4+m)

Solution for 2(6m-12)=3(4+m) equation:

2(6m-12)=3(4+m)

We move all terms to the left:

2(6m-12)-(3(4+m))=0

We add all the numbers together, and all the variables

2(6m-12)-(3(m+4))=0

We multiply parentheses

12m-(3(m+4))-24=0


We calculate terms in parentheses: -(3(m+4)), so:

3(m+4)

We multiply parentheses

3m+12

Back to the equation:

-(3m+12)


We get rid of parentheses

12m-3m-12-24=0

We add all the numbers together, and all the variables

9m-36=0

We move all terms containing m to the left, all other terms to the right

9m=36

m=36/9

m=4