2(6d+3)=18-48-9d

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Solution for 2(6d+3)=18-48-9d equation: 



2(6d+3)=18-48-9d

We move all terms to the left:

2(6d+3)-(18-48-9d)=0

We add all the numbers together, and all the variables

2(6d+3)-(-9d-30)=0

We multiply parentheses

12d-(-9d-30)+6=0

We get rid of parentheses

12d+9d+30+6=0

We add all the numbers together, and all the variables

21d+36=0

We move all terms containing d to the left, all other terms to the right

21d=-36

d=-36/21

d=-1+5/7

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