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2(6-x)4x=x
We move all terms to the left:
2(6-x)4x-(x)=0
We add all the numbers together, and all the variables
2(-1x+6)4x-x=0
We add all the numbers together, and all the variables
-1x+2(-1x+6)4x=0
We multiply parentheses
-8x^2-1x+48x=0
We add all the numbers together, and all the variables
-8x^2+47x=0
a = -8; b = 47; c = 0;
Δ = b2-4ac
Δ = 472-4·(-8)·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-47}{2*-8}=\frac{-94}{-16} =5+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+47}{2*-8}=\frac{0}{-16} =0 $
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