2(6-3x)=12-(8x+2)

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Solution for 2(6-3x)=12-(8x+2) equation: 



2(6-3x)=12-(8x+2)

We move all terms to the left:

2(6-3x)-(12-(8x+2))=0

We add all the numbers together, and all the variables

2(-3x+6)-(12-(8x+2))=0

We multiply parentheses

-6x-(12-(8x+2))+12=0



We calculate terms in parentheses: -(12-(8x+2)), so:

12-(8x+2)

determiningTheFunctionDomain
-(8x+2)+12

We get rid of parentheses

-8x-2+12

We add all the numbers together, and all the variables

-8x+10

Back to the equation:

-(-8x+10)



We get rid of parentheses

-6x+8x-10+12=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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