2(6+7c)=7(1+2c)-5(2c-3)

Solution for 2(6+7c)=7(1+2c)-5(2c-3) equation:

2(6+7c)=7(1+2c)-5(2c-3)

We move all terms to the left:

2(6+7c)-(7(1+2c)-5(2c-3))=0

We add all the numbers together, and all the variables

2(7c+6)-(7(2c+1)-5(2c-3))=0

We multiply parentheses

14c-(7(2c+1)-5(2c-3))+12=0


We calculate terms in parentheses: -(7(2c+1)-5(2c-3)), so:

7(2c+1)-5(2c-3)

We multiply parentheses

14c-10c+7+15

We add all the numbers together, and all the variables

4c+22

Back to the equation:

-(4c+22)


We get rid of parentheses

14c-4c-22+12=0

We add all the numbers together, and all the variables

10c-10=0

We move all terms containing c to the left, all other terms to the right

10c=10

c=10/10

c=1