2(6+2x)=3(x-4)+x

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Solution for 2(6+2x)=3(x-4)+x equation: 



2(6+2x)=3(x-4)+x

We move all terms to the left:

2(6+2x)-(3(x-4)+x)=0

We add all the numbers together, and all the variables

2(2x+6)-(3(x-4)+x)=0

We multiply parentheses

4x-(3(x-4)+x)+12=0



We calculate terms in parentheses: -(3(x-4)+x), so:

3(x-4)+x

We add all the numbers together, and all the variables

x+3(x-4)

We multiply parentheses

x+3x-12

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

4x-4x+12+12=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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