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2(6)+2(2x-3)=2(12)+2(x-1)
We move all terms to the left:
2(6)+2(2x-3)-(2(12)+2(x-1))=0
We multiply parentheses
4x-(212+2(x-1))-6+26=0
We calculate terms in parentheses: -(212+2(x-1)), so:We add all the numbers together, and all the variables
212+2(x-1)
determiningTheFunctionDomain 2(x-1)+212
We multiply parentheses
2x-2+212
We add all the numbers together, and all the variables
2x+210
Back to the equation:
-(2x+210)
4x-(2x+210)+20=0
We get rid of parentheses
4x-2x-210+20=0
We add all the numbers together, and all the variables
2x-190=0
We move all terms containing x to the left, all other terms to the right
2x=190
x=190/2
x=95
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