2(5y+1)+16=6+3(y-7)

Solution for 2(5y+1)+16=6+3(y-7) equation:

2(5y+1)+16=6+3(y-7)

We move all terms to the left:

2(5y+1)+16-(6+3(y-7))=0

We multiply parentheses

10y-(6+3(y-7))+2+16=0


We calculate terms in parentheses: -(6+3(y-7)), so:

6+3(y-7)

determiningTheFunctionDomain
3(y-7)+6

We multiply parentheses

3y-21+6

We add all the numbers together, and all the variables

3y-15

Back to the equation:

-(3y-15)


We add all the numbers together, and all the variables

10y-(3y-15)+18=0

We get rid of parentheses

10y-3y+15+18=0

We add all the numbers together, and all the variables

7y+33=0

We move all terms containing y to the left, all other terms to the right

7y=-33

y=-33/7

y=-4+5/7