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2(5x-8)=3(x-4)
We move all terms to the left:
2(5x-8)-(3(x-4))=0
We multiply parentheses
10x-(3(x-4))-16=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
10x-3x+12-16=0
We add all the numbers together, and all the variables
7x-4=0
We move all terms containing x to the left, all other terms to the right
7x=4
x=4/7
x=4/7
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