2(5x-7)=20+3(x+5)

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Solution for 2(5x-7)=20+3(x+5) equation: 



2(5x-7)=20+3(x+5)

We move all terms to the left:

2(5x-7)-(20+3(x+5))=0

We multiply parentheses

10x-(20+3(x+5))-14=0



We calculate terms in parentheses: -(20+3(x+5)), so:

20+3(x+5)

determiningTheFunctionDomain
3(x+5)+20

We multiply parentheses

3x+15+20

We add all the numbers together, and all the variables

3x+35

Back to the equation:

-(3x+35)



We get rid of parentheses

10x-3x-35-14=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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