2(5x-3)=6+4(x+1)

Solution for 2(5x-3)=6+4(x+1) equation:

2(5x-3)=6+4(x+1)

We move all terms to the left:

2(5x-3)-(6+4(x+1))=0

We multiply parentheses

10x-(6+4(x+1))-6=0


We calculate terms in parentheses: -(6+4(x+1)), so:

6+4(x+1)

determiningTheFunctionDomain
4(x+1)+6

We multiply parentheses

4x+4+6

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)


We get rid of parentheses

10x-4x-10-6=0

We add all the numbers together, and all the variables

6x-16=0

We move all terms containing x to the left, all other terms to the right

6x=16

x=16/6

x=2+2/3