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2(5x-1)=5(2x+2)
We move all terms to the left:
2(5x-1)-(5(2x+2))=0
We multiply parentheses
10x-(5(2x+2))-2=0
We calculate terms in parentheses: -(5(2x+2)), so:We get rid of parentheses
5(2x+2)
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
10x-10x-10-2=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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