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2(5x+4)-11=4x+3(2x+1)
We move all terms to the left:
2(5x+4)-11-(4x+3(2x+1))=0
We multiply parentheses
10x-(4x+3(2x+1))+8-11=0
We calculate terms in parentheses: -(4x+3(2x+1)), so:We add all the numbers together, and all the variables
4x+3(2x+1)
We multiply parentheses
4x+6x+3
We add all the numbers together, and all the variables
10x+3
Back to the equation:
-(10x+3)
10x-(10x+3)-3=0
We get rid of parentheses
10x-10x-3-3=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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