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2(5x+3)=13(3x/4)
We move all terms to the left:
2(5x+3)-(13(3x/4))=0
We add all the numbers together, and all the variables
2(5x+3)-(13(+3x/4))=0
We multiply parentheses
10x-(13(+3x/4))+6=0
We multiply all the terms by the denominator
10x*4))-(13(+3x+6*4))=0
We add all the numbers together, and all the variables
10x*4))-(13(3x+24))=0
We add all the numbers together, and all the variables
10x*4))-(13(3x=0
Wy multiply elements
40x^2=0
a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{80}=0$
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