2(5t-1)=28

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Solution for 2(5t-1)=28 equation: 



2(5t-1)=28

We move all terms to the left:

2(5t-1)-(28)=0

We multiply parentheses

10t-2-28=0

We add all the numbers together, and all the variables

10t-30=0

We move all terms containing t to the left, all other terms to the right

10t=30

t=30/10

t=3

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