2(5c+20)-2c=3(2c+3)+7

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Solution for 2(5c+20)-2c=3(2c+3)+7 equation: 


Simplifying
2(5c + 20) + -2c = 3(2c + 3) + 7

Reorder the terms:
2(20 + 5c) + -2c = 3(2c + 3) + 7
(20 * 2 + 5c * 2) + -2c = 3(2c + 3) + 7
(40 + 10c) + -2c = 3(2c + 3) + 7

Combine like terms: 10c + -2c = 8c
40 + 8c = 3(2c + 3) + 7

Reorder the terms:
40 + 8c = 3(3 + 2c) + 7
40 + 8c = (3 * 3 + 2c * 3) + 7
40 + 8c = (9 + 6c) + 7

Reorder the terms:
40 + 8c = 9 + 7 + 6c

Combine like terms: 9 + 7 = 16
40 + 8c = 16 + 6c

Solving
40 + 8c = 16 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
40 + 8c + -6c = 16 + 6c + -6c

Combine like terms: 8c + -6c = 2c
40 + 2c = 16 + 6c + -6c

Combine like terms: 6c + -6c = 0
40 + 2c = 16 + 0
40 + 2c = 16

Add '-40' to each side of the equation.
40 + -40 + 2c = 16 + -40

Combine like terms: 40 + -40 = 0
0 + 2c = 16 + -40
2c = 16 + -40

Combine like terms: 16 + -40 = -24
2c = -24

Divide each side by '2'.
c = -12

Simplifying
c = -12

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