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2(5c+2)-2c=3(2c=3)=7

We move all terms to the left:

2(5c+2)-2c-(3(2c)=0

We add all the numbers together, and all the variables

-2c+2(5c+2)-(32c=0

We multiply parentheses

-2c+10c-(32c+4=0

We add all the numbers together, and all the variables

8c-(32c+4=0

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