2(5c+1)-48=4c+2

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Solution for 2(5c+1)-48=4c+2 equation:


Simplifying
2(5c + 1) + -48 = 4c + 2

Reorder the terms:
2(1 + 5c) + -48 = 4c + 2
(1 * 2 + 5c * 2) + -48 = 4c + 2
(2 + 10c) + -48 = 4c + 2

Reorder the terms:
2 + -48 + 10c = 4c + 2

Combine like terms: 2 + -48 = -46
-46 + 10c = 4c + 2

Reorder the terms:
-46 + 10c = 2 + 4c

Solving
-46 + 10c = 2 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-46 + 10c + -4c = 2 + 4c + -4c

Combine like terms: 10c + -4c = 6c
-46 + 6c = 2 + 4c + -4c

Combine like terms: 4c + -4c = 0
-46 + 6c = 2 + 0
-46 + 6c = 2

Add '46' to each side of the equation.
-46 + 46 + 6c = 2 + 46

Combine like terms: -46 + 46 = 0
0 + 6c = 2 + 46
6c = 2 + 46

Combine like terms: 2 + 46 = 48
6c = 48

Divide each side by '6'.
c = 8

Simplifying
c = 8

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